temperatureScore property Null safety

int temperatureScore

심부항문 체온 점수를 계산합니다.

Implementation

int get temperatureScore {
  if (temperature < 38.29) {
    return 0;
  } else if (temperature >= 38.29 && temperature < 38.84) {
    return 1;
  } else if (temperature >= 38.84 && temperature < 39.39) {
    return 2;
  } else {
    return 3;
  }
}